

Questions from CBSE Board Paper 2014 for 2015
Q. A wire of resistivity ρ is stretched to double its length. How does it affect the (a) resistance (b) resistivity?
Solution:
(a) wire is stretched to double its length
So, New length of wire l'= 2l
New Area of cross section or thickness of wire A'= A/2
New resistance = r =( ρ x 2l) /(A/ 2) = 4ρl/ A = 4 R
Hence, new resistance = 4r
(b) the resistivity is a property of a material and thus is a constant.
So, in this case, by increasing the length of the wire we are not altering its resistivity. It will remain the same, ρ
Q. A wire of resistance 10 ohm is bent in the form of a closed circle. What is the effective resistance between the two points at the end of any diameter of the circle?
Solution: A wire of resistance 10 ohm is bent in the form of a closed circle
So, R1 = R2 = 5 Ohm form a parallel loop
R' = (R1 R2)/(R1+ R2) = (5x5 )/(5+5) = 2.5 Ohm
Q. List two safety measures commonly used in electric circuits. Explain the main function of each. [CBSE 2014]
Ans: Two safety measures commonly used in electric circuits and appliances are
(i) Electric Fuse: An electric fuse is connected in series it protects the circuit from overloading and prevents it from short circuiting.
(ii) Proper earthing of all electric circuit in which any leakage of current in an electric appliance is transferred to the ground and people using the appliance do not get the shock.
Q. With the help of a circuit diagram prove that when a number of resistors are connected in parallel the reciprocal of the equivalent resistance of the combination is equal to the sum of the reciprocals of the individual resistances of the resistors.
Find the resistance between A and B in the following network [CBSE 2014]
Solution: The resistance between a to and B to C = R1= 2 + 2 = 4 ohm
R2 = 4 Ohm
The resistance between A and B =R' = (R1 R2)/(R1+ R2) = 4x4/(4+4) = 2 Ohm
Q. (a) How does the resistance of a wire change when
(i) its length is tripled ?
(ii) its radius is tripled ?
(iii) its material is changed to one whose resistivity is three times ?
(b) List two reasons why nichrome is used for making heating element of electrical appliances. [CBSE 2014]
Solution: (a)
(i) We know that resistance of wire is directly proportional to length of wire
So,if its length is tripled the resistance increases 3 times
(ii) We know that resistance of wire is inversely proportional to area of cross section of wire
New radius = 3r so,New area increases 9 times
Thus the resistance of a wire decreases 9 times
(ii) R = Pl/A
new resistivity p' = 3p
New Resistance R' = 3Pl/A = 3R
Thus, the resistance of wire increases 3 times
(b) Nichrome is used for making heating element of electrical appliances because:
(i) Nichrome does not oxidize, i. e. burn easily at high temperatures as it has higher melting and boiling point than metals.
(ii) Nichrome has higher resisistivity and consequently a higher resistance. Therefore, it will resist the flow of charges more, and lead to development of heat faster
Q. Mention one reason why tungsten is used for making filament of electric lamp. [CBSE 2014]
Ans: tungsten does not oxidize, i. e. burn easily at high temperatures as it has higher melting and boiling point than metals
Q. List two characteristics of the material to be used in fuse wire. Name the material it is made of. A fuse is always connected in series in an electric circuit ? Justify this statement giving reason [CBSE 2014]
Answer:
two characteristics of the material to be used in fuse wire
(a) Low melting and boiling point (b) high electric resistance
Fuse is generally made up of an alloy of tin and lead
In series connection the current for the entire house pass through the fuse. So, when fuse melts , it breaks down the entire home circuit and no current flows to the household circuitry. Thus, a fuse is always connected in series
Q. A circuit has a line of 5 A. How many lamps of rating 40 W; 220 V can simultaneously run on this line safely ?[CBSE 2014]
Solution : P = VI so, I = P/V = 40/220
No of lamp can simultaneously run on this line safely = 5A/(40/220 )A = 27
Q. Several electric bulbs designed to be used on a 220 V electric supply line, are rated 10 W. How many lamps can be connected in parallel with each other across the two wires of 220 V line if the maximum allowable current is 5 A?
Solution :
Resistance R 1 of the bulb = V^2/p1 = (220)2/10 = 4840 Ohm
Let lamps can be connected in parallel with each other
According to O hm’s law, V = I R
Where, R is the total resistance of the circuit for x number of electric bulbs
R = V/I = 220/5 = 44 Ohm
Number of lamp = 4840/44 = 110
Q. Express work done in an electric field in terms of charge and potential difference. Calculate the amount of work done in carrying a charge of 5 mC against a potential difference of 100 V [CBSE 2014]
Solution : Work dome = charge x potential difference
the amount of work done in carrying a charge of 5 mC against a potential difference of 100 V = 5 × 10^3 × 100 = 0. 5 J
Q. Distinguish between kilowatt and kilowatt hour. For a heater rated at 4.4 kW; 220 V . Calculate the 
(i) current drawn by the heater (ii) resistance of the heater element
(iii) energy consumed by the heater in 5 hours (iv) cost of running the heater if 1 kWh costs Rs. 6.50 [CBSE 2014]
Answer: Kilowatt is the unit of Power where as KiloWatt Hour is the commercial unit of energy.
Given, P = 4.4 kW = 4400 W and V = 220 volts
(i) As P = V /I So, I = P/V = 4400/220 = 20 A
(ii) As P = I^2R So, R = P/I^2 = 4400/(20) 2 = 11 ohms
(iii) since, electric energy = electric power X time = 4.4 kW X 4 hours = 17.6 kWh
(iv) Since, 1KwH costs Rs. 6.50, hence, costs of 17.6 kWh = 17.6 X 6.50 = Rs. 114.4
Q.Distinguish between resistance and resistivity of a conductor.
The resistors are generally made of thin wires of Eureka or Manganin while the wires used in connections are made comparatively thicker and are of copper or aluminium. Why ? Give reason.
What would happen to the resistance of a wire if it is stretched to double its length ? Justify your answer.[CBSE 2014]
Solution :
Resistivity
1. It is the measure of a material’s ability to oppose the flow of current.
2. It depends on the property of the material. Its value is constant for a particular range of temperature.
3. Unit of resistivity is Ohm meter
Resistance
1. It is a measure of the opposition that a circuit (or an electrical element) offers to the flow of electric current.
2. Resistance of a conductor is directly proportional to its length and inversely proportional to its area of cross section.
3. Unit of resistance is Ohm
The resistors are generally made of thin wires of Eureka or Manganin while the wires used in connections are made comparatively thicker and are of copper or aluminium. This is because thicker wire has less resistance than thinner wire
Q. Which has more resistance: 100W bulb or 60W bulb?
Answer. We know that : R = V^2/P
As R is inversely proportional to P for constant V. Thus, the resistance of 60W bulb is more.
Q. Ammeter burns out when connected in parallel. Give reasons.
Answer. Ammeter consists of a wire of low resistance when connected in parallel; a large amount of
current passes through it hence gets burnt i.e. short circuited.
Q.Two fuse wire A and B of the same length are rated 15A and 5A. Which amongst the A and B will be thicker and why?
Answer: The wire A with 15 A rating is thicker. It is because, thicker the wire, less is the resistance and hence it can carry more current.
Q. Tow bulbs marked 200 Watts – 250 V, and 100 Watts – 250 V are joined in series to 250 V supply. Find the power consumed by the circuit
Solution:
The resistance of first and second bulb are R1 = (250)^2/200 and R2 = (250)^2/100
The total resistance when the bulbs are connected in series will be
R = R1+R2 = 250)^2/200 + (250)^2/100 = 312.5 + 625 = 937.5 Ohm
The total power consumption when they joined in series to 250 V supply. The power consumed in the circuit will be,
P = V^2 /R = (250)^2 /937.5 = 66.66 W
Q. What is conductance? HOTS
Ans: The measure of how efficiently electricity travels along a particular pathway via an electrical component is known as conductance.
When a current of one ampere (1 A) passes through a component across which a voltage of one volt (1 V) exists, then the conductance of that component is 1 S. The siemens is, in fact, equivalent to one ampere per volt.
G = I/V
Since, V =IR
G= 1/R
Conductance is actually the inverse or reciprocal of resistance. With this, the higher the resistance, the lesser the degree of conductance. With this idea, a symbol was derived for conductance, "G," and is measured in siemens (S) , formerly known as the mho.
Q. (i) What precautions should be taken to avoid the overloading of domestic electric circuits ?
(ii) An electric oven of 2 kW power rating is operated in a domestic electric circuit that has a current rating of 5A. If the supply voltage is 220V, what result do you expect? Explain.
Ans: (i) Too many high power rating electrical appliances (electric iron, geyser, A.C.) should not be switched on at the same time. ½ + ½ Do not operate too many electrical appliances on a single socket.
(ii) P 5 2 kW 5 2000 W and V 5 220 V ;
P = V /I.
I = P/V = 2000/ 220 = 9A.
Current drawn is very high but the fuse is only of 5A
Therefore the fuse will blow off due to overloading and cutt off the power supply in this circuit.
Q. Resistance of a metal wire of length 1m is 26V at 208C. If the diameter of the wire is 0.3mm, what will be the resistivity of the metal at that temperature ?
Solution: p = 26 x 22/7(1.5 x 10^4)^2 = 1.75 x 10^ 6 m
Q. (a) Why do copper or aluminium wires generally used for electrical transmission and distribution purposes ?
(b) Two wires, one of copper and other of manganin, have equal lengths and equal resistances. Which wire is thicker ? Given that resistivity of copper is lower than that of manganin.
Ans: (a) They have low resistance, so very small amount of energy is wasted in transmission. They are also ductile so can be easily drawn into wires.
(b) p directly proportional to area of cross section
Resistivity of manganin is very large, so it is thicker than copper.
Q. A wire of resistivity ρ is stretched to double its length. How does it affect the (a) resistance (b) resistivity?
Solution:
(a) wire is stretched to double its length
So, New length of wire l'= 2l
New Area of cross section or thickness of wire A'= A/2
New resistance = r =( ρ x 2l) /(A/ 2) = 4ρl/ A = 4 R
Hence, new resistance = 4r
(b) the resistivity is a property of a material and thus is a constant.
So, in this case, by increasing the length of the wire we are not altering its resistivity. It will remain the same, ρ
Q. A wire of resistance 10 ohm is bent in the form of a closed circle. What is the effective resistance between the two points at the end of any diameter of the circle?
Solution: A wire of resistance 10 ohm is bent in the form of a closed circle
So, R1 = R2 = 5 Ohm form a parallel loop
R' = (R1 R2)/(R1+ R2) = (5x5 )/(5+5) = 2.5 Ohm
Q. List two safety measures commonly used in electric circuits. Explain the main function of each. [CBSE 2014]
Ans: Two safety measures commonly used in electric circuits and appliances are
(i) Electric Fuse: An electric fuse is connected in series it protects the circuit from overloading and prevents it from short circuiting.
(ii) Proper earthing of all electric circuit in which any leakage of current in an electric appliance is transferred to the ground and people using the appliance do not get the shock.
Q. With the help of a circuit diagram prove that when a number of resistors are connected in parallel the reciprocal of the equivalent resistance of the combination is equal to the sum of the reciprocals of the individual resistances of the resistors.
Find the resistance between A and B in the following network [CBSE 2014]
Solution: The resistance between a to and B to C = R1= 2 + 2 = 4 ohm
R2 = 4 Ohm
The resistance between A and B =R' = (R1 R2)/(R1+ R2) = 4x4/(4+4) = 2 Ohm
Q. (a) How does the resistance of a wire change when
(i) its length is tripled ?
(ii) its radius is tripled ?
(iii) its material is changed to one whose resistivity is three times ?
(b) List two reasons why nichrome is used for making heating element of electrical appliances. [CBSE 2014]
Solution: (a)
(i) We know that resistance of wire is directly proportional to length of wire
So,if its length is tripled the resistance increases 3 times
(ii) We know that resistance of wire is inversely proportional to area of cross section of wire
New radius = 3r so,New area increases 9 times
Thus the resistance of a wire decreases 9 times
(ii) R = Pl/A
new resistivity p' = 3p
New Resistance R' = 3Pl/A = 3R
Thus, the resistance of wire increases 3 times
(b) Nichrome is used for making heating element of electrical appliances because:
(i) Nichrome does not oxidize, i. e. burn easily at high temperatures as it has higher melting and boiling point than metals.
(ii) Nichrome has higher resisistivity and consequently a higher resistance. Therefore, it will resist the flow of charges more, and lead to development of heat faster
Q. Mention one reason why tungsten is used for making filament of electric lamp. [CBSE 2014]
Ans: tungsten does not oxidize, i. e. burn easily at high temperatures as it has higher melting and boiling point than metals
Q. List two characteristics of the material to be used in fuse wire. Name the material it is made of. A fuse is always connected in series in an electric circuit ? Justify this statement giving reason [CBSE 2014]
Answer:
two characteristics of the material to be used in fuse wire
(a) Low melting and boiling point (b) high electric resistance
Fuse is generally made up of an alloy of tin and lead
In series connection the current for the entire house pass through the fuse. So, when fuse melts , it breaks down the entire home circuit and no current flows to the household circuitry. Thus, a fuse is always connected in series
Q. A circuit has a line of 5 A. How many lamps of rating 40 W; 220 V can simultaneously run on this line safely ?[CBSE 2014]
Solution : P = VI so, I = P/V = 40/220
No of lamp can simultaneously run on this line safely = 5A/(40/220 )A = 27
Q. Several electric bulbs designed to be used on a 220 V electric supply line, are rated 10 W. How many lamps can be connected in parallel with each other across the two wires of 220 V line if the maximum allowable current is 5 A?
Solution :
Resistance R 1 of the bulb = V^2/p1 = (220)2/10 = 4840 Ohm
Let lamps can be connected in parallel with each other
According to O hm’s law, V = I R
Where, R is the total resistance of the circuit for x number of electric bulbs
R = V/I = 220/5 = 44 Ohm
Number of lamp = 4840/44 = 110
Q. Express work done in an electric field in terms of charge and potential difference. Calculate the amount of work done in carrying a charge of 5 mC against a potential difference of 100 V [CBSE 2014]
Solution : Work dome = charge x potential difference
the amount of work done in carrying a charge of 5 mC against a potential difference of 100 V = 5 × 10^3 × 100 = 0. 5 J
Q. Distinguish between kilowatt and kilowatt hour. For a heater rated at 4.4 kW; 220 V . Calculate the 
(i) current drawn by the heater (ii) resistance of the heater element
(iii) energy consumed by the heater in 5 hours (iv) cost of running the heater if 1 kWh costs Rs. 6.50 [CBSE 2014]
Answer: Kilowatt is the unit of Power where as KiloWatt Hour is the commercial unit of energy.
Given, P = 4.4 kW = 4400 W and V = 220 volts
(i) As P = V /I So, I = P/V = 4400/220 = 20 A
(ii) As P = I^2R So, R = P/I^2 = 4400/(20) 2 = 11 ohms
(iii) since, electric energy = electric power X time = 4.4 kW X 4 hours = 17.6 kWh
(iv) Since, 1KwH costs Rs. 6.50, hence, costs of 17.6 kWh = 17.6 X 6.50 = Rs. 114.4
Q.Distinguish between resistance and resistivity of a conductor.
The resistors are generally made of thin wires of Eureka or Manganin while the wires used in connections are made comparatively thicker and are of copper or aluminium. Why ? Give reason.
What would happen to the resistance of a wire if it is stretched to double its length ? Justify your answer.[CBSE 2014]
Solution :
Resistivity
1. It is the measure of a material’s ability to oppose the flow of current.
2. It depends on the property of the material. Its value is constant for a particular range of temperature.
3. Unit of resistivity is Ohm meter
Resistance
1. It is a measure of the opposition that a circuit (or an electrical element) offers to the flow of electric current.
2. Resistance of a conductor is directly proportional to its length and inversely proportional to its area of cross section.
3. Unit of resistance is Ohm
The resistors are generally made of thin wires of Eureka or Manganin while the wires used in connections are made comparatively thicker and are of copper or aluminium. This is because thicker wire has less resistance than thinner wire
Q. Which has more resistance: 100W bulb or 60W bulb?
Answer. We know that : R = V^2/P
As R is inversely proportional to P for constant V. Thus, the resistance of 60W bulb is more.
Q. Ammeter burns out when connected in parallel. Give reasons.
Answer. Ammeter consists of a wire of low resistance when connected in parallel; a large amount of
current passes through it hence gets burnt i.e. short circuited.
Q.Two fuse wire A and B of the same length are rated 15A and 5A. Which amongst the A and B will be thicker and why?
Answer: The wire A with 15 A rating is thicker. It is because, thicker the wire, less is the resistance and hence it can carry more current.
Q. Tow bulbs marked 200 Watts – 250 V, and 100 Watts – 250 V are joined in series to 250 V supply. Find the power consumed by the circuit
Solution:
The resistance of first and second bulb are R1 = (250)^2/200 and R2 = (250)^2/100
The total resistance when the bulbs are connected in series will be
R = R1+R2 = 250)^2/200 + (250)^2/100 = 312.5 + 625 = 937.5 Ohm
The total power consumption when they joined in series to 250 V supply. The power consumed in the circuit will be,
P = V^2 /R = (250)^2 /937.5 = 66.66 W
Q. What is conductance? HOTS
Ans: The measure of how efficiently electricity travels along a particular pathway via an electrical component is known as conductance.
When a current of one ampere (1 A) passes through a component across which a voltage of one volt (1 V) exists, then the conductance of that component is 1 S. The siemens is, in fact, equivalent to one ampere per volt.
G = I/V
Since, V =IR
G= 1/R
Conductance is actually the inverse or reciprocal of resistance. With this, the higher the resistance, the lesser the degree of conductance. With this idea, a symbol was derived for conductance, "G," and is measured in siemens (S) , formerly known as the mho.
Q. (i) What precautions should be taken to avoid the overloading of domestic electric circuits ?
(ii) An electric oven of 2 kW power rating is operated in a domestic electric circuit that has a current rating of 5A. If the supply voltage is 220V, what result do you expect? Explain.
Ans: (i) Too many high power rating electrical appliances (electric iron, geyser, A.C.) should not be switched on at the same time. ½ + ½ Do not operate too many electrical appliances on a single socket.
(ii) P 5 2 kW 5 2000 W and V 5 220 V ;
P = V /I.
I = P/V = 2000/ 220 = 9A.
Current drawn is very high but the fuse is only of 5A
Therefore the fuse will blow off due to overloading and cutt off the power supply in this circuit.
Q. Resistance of a metal wire of length 1m is 26V at 208C. If the diameter of the wire is 0.3mm, what will be the resistivity of the metal at that temperature ?
Solution: p = 26 x 22/7(1.5 x 10^4)^2 = 1.75 x 10^ 6 m
Q. (a) Why do copper or aluminium wires generally used for electrical transmission and distribution purposes ?
(b) Two wires, one of copper and other of manganin, have equal lengths and equal resistances. Which wire is thicker ? Given that resistivity of copper is lower than that of manganin.
Ans: (a) They have low resistance, so very small amount of energy is wasted in transmission. They are also ductile so can be easily drawn into wires.
(b) p directly proportional to area of cross section
Resistivity of manganin is very large, so it is thicker than copper.
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