

Q. In a group of four members. Find the probability of having at least two males :
Solution: Sample Space = {FFFF, FFFM, FFMF, FMFF, MFFF, FFMM, FMFM, MFMF, FMMF,
MFFM, MMFF, FMMM, MFMM, MMFM, MMMF, MMMM}
Total number of outcomes = 16
Total favorable outcomes = {FFMM, FMFM, MFMF, FMMF, MFFM, MMFF, FMMM,
MFMM, MMFM, MMMF, MMMM} = 11
The probability of having at least two girls in the group = 11/16
Q. Four coins are tossed together. What is the total number of possible outcomes? Give the sample space of the event.
Solution: The sample space of four coins tossed together is given by,
HHHH, HHHT, HHTH, HTHH, THHH, HHTT, HTHT, THTH, HTTH, THHT, TTHH, HTTT, THTT, TTHT, TTTH, TTTT
Total number of possible outcomes = 16
Solution: Sample Space = {FFFF, FFFM, FFMF, FMFF, MFFF, FFMM, FMFM, MFMF, FMMF,
MFFM, MMFF, FMMM, MFMM, MMFM, MMMF, MMMM}
Total number of outcomes = 16
Total favorable outcomes = {FFMM, FMFM, MFMF, FMMF, MFFM, MMFF, FMMM,
MFMM, MMFM, MMMF, MMMM} = 11
The probability of having at least two girls in the group = 11/16
Q. Four coins are tossed together. What is the total number of possible outcomes? Give the sample space of the event.
Solution: The sample space of four coins tossed together is given by,
HHHH, HHHT, HHTH, HTHH, THHH, HHTT, HTHT, THTH, HTTH, THHT, TTHH, HTTT, THTT, TTHT, TTTH, TTTT
Total number of possible outcomes = 16
10th Maths SA2 Chapter wise Test Papers Links 

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