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1. A bag contains 100 cards numbered 1 to 100. A card is drawn at random from the bag. What is the probability that the number on the card is a perfect cube ? (a) 1/20 (b) 3/50 (c) 1/25 (d) 7/100
2. If three coins are tossed simultaneously, what is the probability of getting at most one tail ?
(a) 3/8 (b) 4/8 (c) 5/8 (d) 7/8
3.In a single throw of two dice, the probability of getting 12 as a product of two numbers obtained is :
(a) 1/9 (b) 2/9 (c)4/9 (d) 5/9
4.In a lottery, there are 5 prizes and 20 blanks. The probability of getting a prize is :
(a) 1/4 (b) 1/20 (c) 1/25 (d) 1/5
5.A bag contains 5 red balls and n green balls. If the probability of drawing a green ball is three times that of a red ball, then the value of n is : 1 (a) 18 (b) 15 (c) 10 (d) 20
1.Number of Computers 1-10 11 -20 21-50 51- 100 101 and more
Number of Schools 250 200 290 180 80
One school is chosen at random. Then : (i) Find the probability that the school chosen at random has more than 100 computers. (ii) (a) Find the probability that the school chosen at random has 50 or fewer computers.
OR (ii) (b) Find the probability that the school chosen at random has no more than 20 computers.
(iii) Find the probability that the school chosen at random has 10 or less than 10 computers.
2.20 cards, numbered 1 to 20 are mixed thoroughly and then a card is drawn at random. Find the probability that the number on the drawn card is a multiple of 3 or 5.
Q. In a group of four members. Find the probability of having at least two males :
Solution: Sample Space = {FFFF, FFFM, FFMF, FMFF, MFFF, FFMM, FMFM, MFMF, FMMF,
MFFM, MMFF, FMMM, MFMM, MMFM, MMMF, MMMM}
Total number of outcomes = 16
Total favorable outcomes = {FFMM, FMFM, MFMF, FMMF, MFFM, MMFF, FMMM,
MFMM, MMFM, MMMF, MMMM} = 11
The probability of having at least two girls in the group = 11/16
Q. Four coins are tossed together. What is the total number of possible outcomes? Give the sample space of the event.
Solution: The sample space of four coins tossed together is given by,
HHHH, HHHT, HHTH, HTHH, THHH, HHTT, HTHT, THTH, HTTH, THHT, TTHH, HTTT, THTT, TTHT, TTTH, TTTT
Total number of possible outcomes = 16
Solution: Sample Space = {FFFF, FFFM, FFMF, FMFF, MFFF, FFMM, FMFM, MFMF, FMMF,
MFFM, MMFF, FMMM, MFMM, MMFM, MMMF, MMMM}
Total number of outcomes = 16
Total favorable outcomes = {FFMM, FMFM, MFMF, FMMF, MFFM, MMFF, FMMM,
MFMM, MMFM, MMMF, MMMM} = 11
The probability of having at least two girls in the group = 11/16
Q. Four coins are tossed together. What is the total number of possible outcomes? Give the sample space of the event.
Solution: The sample space of four coins tossed together is given by,
HHHH, HHHT, HHTH, HTHH, THHH, HHTT, HTHT, THTH, HTTH, THHT, TTHH, HTTT, THTT, TTHT, TTTH, TTTT
Total number of possible outcomes = 16
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