Find the ratio in which line y = x divides the line segment joining the points (6, 3) and (1, 6) Step 1: Let's assume the ratio in which the line divides the segment AB is 𝒌: 𝟏 Step 2: Find the coordinates of the point of intersection P as x = (𝒌+𝟔)/( k + 1); y = (𝟔𝒌 – 3)/(k + 1) Step 3: The point P lies on the line Y = X, so you equated the x-coordinate and the y-coordinate of point P So, P(x, y) lies on y = x k + 6 = 6k –3 k = 𝟗 /𝟓 Ratio is 9 : 5 More related material Class 10 chapter Co-Ordinate
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