Class O7 Maths Half year question paper 2023-24 DAV School #maths #class7 Get ready to do really well in your math exams with the special DAV Class 7 Maths Half Year Question Paper 2023-24. This practice paper is made especially for you to feel more confident and do great in math. You can use our helpful educational resources at JSUNIL TUTORIAL to prepare for success. D.A.V. PUBLIC SCHOOLS BIHAR ZONE Half— Yearly Examination: 2023-2024 ' Class: VII Subject - MATHEMATICS F.M.- 70 General instructions:- > All questions are compulsory. The question paper consist of 4 sections namely A,B,C,D ➢ Each question of Section -A carries 1 mark ➢ Each q;lestion of Section -B carries 2 marks >➢ Each question of Section-C carries 3 marks ➢ Each question of Section -D carries 4 marks Section - A (1x12=12) MULTIPLE CHOICE QUESTIONS 1. How many lines of symmetry in a circle are: a. Infinite b. two c. three d. one 2. Identity element for subtraction of rational number is a. 1 b. 0 c. -1 d. does not exst. 3. The point of concurrence of the medians of a triangle is called a.Orthocentre b. Centre c. Centroid d. Incentre 4. Reciprocal of 1 is a. 1 b. I. ,c. o - d. None of these 5. If triangle ABC is congruent to triangle EDEF ,then < A = ----and AC = --- a. < E ,DF b. <D ,EF c. E< ,DE d. D< ,DF You may also Download New Papers
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1. Q. A train pass a pole in 15 second and a platform 100 m long in 25 second. Find the speed of train and length of train?
Solution: Let the speed of train = x m/s Distance travel by train to cross pole = Length of train , time = 15 sec => 15x = Length of train Distance travel by train to cross platform = Length of train + Length of platform = Length of train + 100,time = 25 sec 25x = 15 x + 100 => 25x – 15x = 100 => 10x = 100 => x = 100/10 = 10m/s Length of train = 15x =15 x 10 = 150m Do yourself: A train passes an electric pole in 10 seconds and a 130 m long platform in 20 seconds. How should I calculate the length of the train? Q.2. A train 50 metres long passes a platform 100 metres long in 10 seconds. The speed of the train? Solution: Distance travel by train to cross platform = Length of train + Length of platform = 50 + 100 = 150m,,time = 10 sec Speed = d/t = 150/10= 15m/s Q.3. A train moves with a speed of 108 km/h. Find Its speed in metres per second? Solution: Speed = 108 x (1000m/3600sec) = 30m/s Q.4. In what time will a train 100 metres long cross an electric pole, if its speed be 144 km/hr? Solution: Speed = 144 x (1000m/3600sec) = 40m/s Distance travel by train to cross pole = Length of train = 100m Time =distance / time = 100/40 = 2.5sec Q.5. A train covers a distance of 12 km in 10 minutes. If it takes 6 seconds to pass a telegraph post, Find the length of the train ? Solution: Time = 10min = 10 x 60 = 600sec , distance = 12km = 12000m Speed of train = 12000m/600sec = 20m/s Length of train = Distance travel by train to cross a telegraph post = speed x time = 20 x 6 = 120m Q.6. A train 110 metres long is running with a speed of 60 km/h. In what time will it pass a man who is running at 6 km/h in the direction opposite to that in which the train is going? Solution: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr = 66 x (5/18) m/s = 55/3m/s Time taken to pass the man = Distance/speed = 110 m/ (55/3)m/s = (110x3)/55 = 6 sec Q.7.Two trains 200 m and 150 m long are running on parallel rails at the rate of 40 km/h and 45 km/h respectively. In how much time will they cross each other, if they are running in the same direction? Solution: Relative speed of trains = (45 - 40) km/h = 5 km/h = 5 x(5/18 )m/s = 25/18m/s Total distance covered = Sum of lengths of trains = 200 + 150 = 350 m. Time taken = distance /speed = 350 /(25/18) = (350 x 18) /5 = 252 sec = 4 min 12sec |
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