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X Trigonometry Introduction and identities Test Paper  1
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DELHI PUBLIC SCHOOL (R.K. PURAM) SA 1 Question Paper (2015 – 2016) Abu Dhabi Indian school maths paper sa1 for session 201516 (pdf links given below) 10th SA1 CBSE Original Maths Abu Dhabi Indian school Paper 20152016
Download pdf File Class 10 Mathematics 2015 Sample Paper  5 Download File Mathematics CBSE 2014 – 2015 Class 10 SA1 Question Papers – Conducted in different CBSE schools19/9/2014 Mathematics Class 10 SA1 Question Papers Conducted in different CBSE Schools _2014 – 2015 CBSE Board 2014 SA1 Original papers of mathematics for Class 10th conducted in different CBSE schools
10th SA1 Original Maths Paper 2014_20151 10th SA1 Original Maths Paper 2014_20152 10th SA1 Original Maths Paper 2014_20153 Download File Posts with label X Chapter : Introduction toTrigonometry.
X Trigonometry CBSE Test Paper1 X Trigonometry CBSE Test Paper2 X Trigonometry CBSE Test Paper 3 X Trigonometry CBSE Test Paper4 X Trigonometry CBSE Test Paper  5 X Trigonometry CBSE Test Paper  6 X Trigonometry CBSE Test Paper 7 X Trigonometry CBSE Test Paper  8 Searches related to trigonometry for class 10 project on trigonometry for class 10 trigonometry for class 10 pdf trigonometry basics trigonometry formulas ppt on trigonometry for class 10 trigonometry for class 10 cbse trigonometry for class 10 wikipedia introduction to trigonometry for class 10 1. EQUATION: The statement of equality is called an equation. 2. Linear equation in one variable: An equation of the form ax+b=0,where a,b are real numbers,(a≠0) is called a linear equation in one variable. 3. Linear equation in two variables: An equation of the form ax+by+c=0, where a,b,c are real numbers(a≠0,b≠0)is called a linear equation in two variables x and y. 4. Consistent system of linear equations: A system of two linear equations in two unknowns is said to be consistent if it has at least one solution. 5.Inconsistent system of linear equations: if a system has no solution, then it is called inconsistent. The system of a pair of linear equations a1 x+b1 y+c1 =0 a2 x +b2y+c2 =0 (i) has no solution. If a1/a2 = b1/b2 ≠ c1/c2 (ii) has an infinite number of solutions If a1/a2 = b1/b2 = c1/c2 (iii) has exactly one solution. If a1/a2 ≠ b1/b2 6. Algebraic methods: (i)Method of substitution (ii)Method of elimination by addition or subtraction (iii) Method of cross multiplication for: a1 x+b1 y+c1 =0 a2 x +b2y+c2 =0 X= (b1c2 – b2c1) /(a1b2 – a2b1) , y = (c1a2 – c2a1) / a1b2  a2b1 More........ Searches related to PAIR OF LINEAR EQUATIONS IN TWO VARIABLES class 10
pair of linear equations in two variables class 10 ppt pair of linear equations in two variables class 10 solutions pair of linear equations in two variables class 10 ncert solutions pair of linear equations in two variables cbse pair of linear equations in two variables questions pair of linear equations in two variables class 10 questions pair of linear equations in two variables class 10 word problems pair of linear equations in two variables class 10 extra questions with solutions Q. ab+bc+ca=0 find value 1/(b2ac ) + 1/(c2ab) + 1/(a2bc)Solution: ab+bc+ca=0 find value 1/(a2bc ) + 1/(c2ab) + 1/(a2bc) Put ac = ab + bc ; ab = ac+ bc and bc =ab + ac you get : 1/(a2bc (ab + bc + ca)/[(a+b+c)(abc)] put, ab+bc+ca=0 you get value = 0/[(a+b+c)(abc)] = 0 Q. A class of 20 boys and 15 girls is divided into n groups so that each group has x boys and y girls. Find x ,y and n.
Sol: n(x+y) = 20 + 15 = 35 Total boys = nx = 20 Þ nx = 2 x 10 = 4 x 5 = 10 x 2 Similarly, Total girls = ny = 15 Þ 3 x 5 The possible value of n may be n = 5 x = 4 and y = 5 OR, Hcf of 20 and 15 is 5 Þ No. of group will be n =5 then Total girls = ny = 15 Þ 3 x 5 The possible value of n may be n = 5 x = 4 and y = 5 Q. The pair of equations y=0 and y= 5 has 1.one solution 2.two solutions 3.infinitely many solutions 4.no solution Ans: o.x + y = 0 0.x + y = 5 therefore, a1/a2 = b1/b2 ≠ c1/c2 Þ The pair of equations y=0 and y= 5 has no solution Q. If secA + tanA = 1/x find the value of SecA and tanA Q. There are 20 cars and motorcycle in a parking lot. If there are 56 wheels together find the no of cars and motorcycles Ans: Le t the no. of car is x then no. of motorcycle will be (20x) A/Q, 4x + 2(20x) = 56 Þ x = 8 the no. of car is x = 8 then no. of motorcycle will be (20x) = 208 = 12 Q. If constant term in Quardatic polynomial is zero ,then prove that one of its zero is zero Sol: let the quadratic polynomial be P(x) = a x2 + bx + c Þ P(x) = a x2 + bx [since the constant term is zero] Now P(0) = 0 + 0 = 0 Thus, 0 is one zero of p(x). Q. If p(x) = ax2 + bx +c and a + c = b, then one of the zeroes is (a) b/a (b) c/a (c) c/a (d) b/a Sol: c/a Q. if asin2q + bcos2 q = c , then sow that cot2q = (ca)/(bc) ab + ac ab + ac (ab + bc + ca)/[(a+b+c)(abc)] put, ab+bc+ca=0 you get value = 0/[(a+b+c)(abc)] = 0 Q. A class of 20 boys and 15 girls is divided into n groups so that each group has x boys and y girls. Find x ,y and n. Sol: n(x+y) = 20 + 15 = 35 Total boys = nx = 20 Þ nx = 2 x 10 = 4 x 5 = 10 x 2 Similarly, Total girls = ny = 15 Þ 3 x 5 The possible value of n may be n = 5 x = 4 and y = 5 OR, Hcf of 20 and 15 is 5 Þ No. of group will be n =5 then Total girls = ny = 15 Þ 3 x 5 The possible value of n may be n = 5 x = 4 and y = 5 Q. The pair of equations y=0 and y= 5 has 1.one solution 2.two solutions 3.infinitely many solutions 4.no solution Ans: o.x + y = 0 0.x + y = 5 therefore, a1/a2 = b1/b2 ≠ c1/c2 Þ The pair of equations y=0 and y= 5 has no solution Q. If secA + tanA = 1/x find the value of SecA and tanA Q. There are 20 cars and motorcycle in a parking lot. If there are 56 wheels together find the no of cars and motorcycles Ans: Le t the no. of car is x then no. of motorcycle will be (20x) A/Q, 4x + 2(20x) = 56 Þ x = 8 the no. of car is x = 8 then no. of motorcycle will be (20x) = 208 = 12 Q. If constant term in Quardatic polynomial is zero ,then prove that one of its zero is zero Sol: let the quadratic polynomial be P(x) = a x2 + bx + c Þ P(x) = a x2 + bx [since the constant term is zero] Now P(0) = 0 + 0 = 0 Thus, 0 is one zero of p(x). Q. If p(x) = ax2 + bx +c and a + c = b, then one of the zeroes is (a) b/a (b) c/a (c) c/a (d) b/a Sol: c/a Q. if asin2q + bcos2 q = c , then sow that cot2q = (ca)/(bc) 1. What is the largest number that divides 245 and 1029 , leaving remainder 5 in each case? (a) 16 (b) 16 (c) 19 (d) 5 2. If p is a prime number and p divides a2(a is a positive integer),then which of the following is true: (a) p does not divide a (b) p divides a (c) p2 divides a (d) p divides a 3. If ax + by = a2 – b2 and bx + ay = 0,then value of (x +y) is : (a) a2 – b2 (b) b a (c) ab (d) a2 + b2 4. The pair of equation y = 0 and y = 5 has (a) one solution (b) two solution (c) infinitely many solution (d) No solution 5. The length of the diagonal of rhombus are 24cm and 32 cm . The length of the altitude of the rhombus in cm is : (a) 12 (b) 12.8 (c) 19 (d) 19.2 6. Sin 200 Cos 700 + Cos 200 Sin 700 is (a) 2 (b) 1 (c) 0 (d) 2 7. If tan + cot = 2 then tan2 + cot2 is (a) 4 (b) 6 (c) 2 (d) 1 8. If “less than” type and “more than type” of Ogive intersect each other at (20.5,15.5), than the median of the given data is : (a) 36.0 (b) 20.0 (c) 15.5 (d) 5.5

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